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11y^2-78y-80=0
a = 11; b = -78; c = -80;
Δ = b2-4ac
Δ = -782-4·11·(-80)
Δ = 9604
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9604}=98$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-78)-98}{2*11}=\frac{-20}{22} =-10/11 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-78)+98}{2*11}=\frac{176}{22} =8 $
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